1-(4-Hydroxycyclohexyl)ethanone

Catalog No.: 
ACDZPC674
CAS No.: 
15580-01-5
Molecular Formula: 
C8H14O2
Molecular Weight: 
142.20
1-(4-Hydroxycyclohexyl)ethanone structure diagram
Pack SizePurityList PriceYour PriceGlobal StockUS StockQuantity
100mg95%$107.00In stockInquiry
250mg95%$214.00In stockInquiry
1g95%$530.00In stockInquiry

Products of AiFChem are all designed for scientific research only. Under no circumstances do we provide products or services for animal or personal utilization.

Product Information

Product Name1-(4-Hydroxycyclohexyl)ethanone
IUPAC Name1-(4-hydroxycyclohexyl)ethan-1-one
MDL No.MFCD00465670
Molecular FormulaC8H14O2
Molecular Weight142.20
SMILESCC(=O)C1CCC(O)CC1
InChI KeyLDHQMPWYKOPGCI-UHFFFAOYSA-N
Synonym4-Hydroxy-1-acetyl-cyclohexan;1-(4-Hydroxycyclohexyl)ethanone;Ethanone, 1-(4-hydroxycyclohexyl)-;1-(4-hydroxycyclohexyl)ethan-1-one
CAS No.15580-01-5
PubChem CID13770153

Safety Data

Pictogram
Harmful or irritant
Signal Word
Warning
Hazard Statement(s)
H315-H319
Precautionary Statement(s)
P264-P280-P302+P352-P305+P351+P338-P332+P313-P337+P313-P362+P364

Synthetic Route by SureRoute

1. ACDZPC674 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. ACJUCS295 route compound structure diagram
    ACJUCS29599-93-4In Stock
  2. Then
  3. ACDZPC674 route product structure diagram
    ACDZPC67415580-01-5In Stock
Inquiry

2. ACDZPC674 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Plus
  3. ACMNJL410 route compound structure diagram
    ACMNJL41017419-81-7In Stock
  4. Plus
  5. reactant_3 route compound structure diagram
    --
  6. Then
  7. ACDZPC674 route product structure diagram
    ACDZPC67415580-01-5In Stock
Inquiry

3. ACDZPC674 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Then
  3. ACDZPC674 route product structure diagram
    ACDZPC67415580-01-5In Stock
Inquiry

Comments (0)