5-(Thiazol-5-yl)nicotinaldehyde

Catalog No.: 
ACOBYJ109
CAS No.: 
1346687-57-7
Molecular Formula: 
C9H6N2OS
Molecular Weight: 
190.23
5-(Thiazol-5-yl)nicotinaldehyde structure diagram
Pack SizePurityList PriceYour PriceGlobal StockUS StockQuantity
250mg95%$126.00InquiryInquiry
1g95%$400.00InquiryInquiry
5g95%$1980.00InquiryInquiry

Products of AiFChem are all designed for scientific research only. Under no circumstances do we provide products or services for animal or personal utilization.

Product Information

Product Name5-(Thiazol-5-yl)nicotinaldehyde
IUPAC Name5-(thiazol-5-yl)nicotinaldehyde
Molecular FormulaC9H6N2OS
Molecular Weight190.23
SMILESO=CC1=CN=CC(C2=CN=CS2)=C1
InChI KeyZIKDOIWRDJLXHD-UHFFFAOYSA-N
Synonym5-(Thiazol-5-yl)nicotinaldehyde;5-(1,3-thiazol-5-yl)pyridine-3-carbaldehyde;3-Pyridinecarboxaldehyde, 5-(5-thiazolyl)-
CAS No.1346687-57-7

Safety Data

Pictogram
Harmful or irritant
Signal Word
Warning
Hazard Statement(s)
H302-H315-H319-H335
Precautionary Statement(s)
P261-P264-P270-P271-P280-P302+P352-P304+P340-P305+P351+P338-P312-P330-P362-P403+P233-P501

Synthetic Route by SureRoute

1. ACOBYJ109 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. ACDQSI627 route compound structure diagram
    ACDQSI627113118-81-3In Stock
  2. Plus
  3. ACRKQL829 route compound structure diagram
    ACRKQL829942190-81-0In Stock
  4. Then
  5. ACOBYJ109 route product structure diagram
    ACOBYJ1091346687-57-7
Inquiry

2. ACOBYJ109 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Plus
  3. ACDQSI627 route compound structure diagram
    ACDQSI627113118-81-3In Stock
  4. Then
  5. ACOBYJ109 route product structure diagram
    ACOBYJ1091346687-57-7
Inquiry

3. ACOBYJ109 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Then
  3. ACOBYJ109 route product structure diagram
    ACOBYJ1091346687-57-7
Inquiry

Comments (0)