trans-4-Phenylcyclohexanecarboxylic acid

Catalog No.: 
ACRUMY035
CAS No.: 
1466-73-5
Molecular Formula: 
C13H16O2
Molecular Weight: 
204.27
trans-4-Phenylcyclohexanecarboxylic acid structure diagram
Pack SizePurityList PriceYour PriceGlobal StockUS StockQuantity
50mg98%
100mg98%
250mg98%
1g98%

Products of AiFChem are all designed for scientific research only. Under no circumstances do we provide products or services for animal or personal utilization.

Product Information

Product Nametrans-4-Phenylcyclohexanecarboxylic acid
IUPAC Name(1r,4r)-4-phenylcyclohexane-1-carboxylic acid
MDL No.MFCD24479551
Molecular FormulaC13H16O2
Molecular Weight204.27
SMILESO=C([C@H]1CC[C@H](C2=CC=CC=C2)CC1)O
InChI KeySYYSTPDYCASVSQ-HAQNSBGRSA-N
Synonym(1r,4r)-4-phenylcyclohexane-1-carboxylic acid;trans-4-henylcyclohexanecarboxylic acid;trans-4-phenyl cyclohexanecarboxylic acid;trans-4-Phenylcyclohexane-1-carboxylic acid;SYYSTPDYCASVSQ-HAQNSBGRSA-N;Cyclohexanecarboxylic acid, 4-phenyl-, trans-;Atovaquone Impurity 23
CAS No.1466-73-5

Safety Data

Pictogram
Harmful or irritant
Signal Word
Warning
Hazard Statement(s)
H302-H315-H319-H335
Precautionary Statement(s)
P261-P264-P270-P271-P280-P301+P312-P302+P352-P304+P340-P305+P351+P338-P330-P332+P313-P337+P313-P362-P403+P233-P405-P501

Synthetic Route by SureRoute

1. ACRUMY035 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Then
  3. ACRUMY035 route product structure diagram
    ACRUMY0351466-73-5In Stock
Inquiry

2. ACRUMY035 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Then
  3. ACRUMY035 route product structure diagram
    ACRUMY0351466-73-5In Stock
Inquiry

3. ACRUMY035 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Then
  3. ACRUMY035 route product structure diagram
    ACRUMY0351466-73-5In Stock
Inquiry

Comments (0)