(E)-1-Ethyl-2-((1-ethylquinolin-2(1H)-ylidene)methyl)quinolin-1-ium iodide

Catalog No. :
ACCOKV517
CAS No. :
63902-24-9
Molecular Formula :
C23H23IN2
Molecular Weight :
454.36

IUPAC Name:(E)-1-ethyl-2-((1-ethylquinolin-2(1H)-ylidene)methyl)quinolin-1-ium iodide

(E)-1-Ethyl-2-((1-ethylquinolin-2(1H)-ylidene)methyl)quinolin-1-ium iodide structure diagram
Pack SizePurityList PriceYour PriceGlobal StockUS StockQuantity
250mg98%$62.00Login to see priceIn stockInquiry
1g98%$148.00Login to see priceIn stockInquiry
5g98%$592.00Login to see priceInquiryInquiry

Products of AiFChem are all designed for scientific research only. Under no circumstances do we provide products or services for animal or personal utilization.

Product Information

Product Name(E)-1-Ethyl-2-((1-ethylquinolin-2(1H)-ylidene)methyl)quinolin-1-ium iodide
IUPAC Name(E)-1-ethyl-2-((1-ethylquinolin-2(1H)-ylidene)methyl)quinolin-1-ium iodide
MDL No.MFCD00011971
Molecular FormulaC23H23IN2
Molecular Weight454.36
SMILESCCN1/C(C=CC2=C1C=CC=C2)=C/C3=CC=C4C=CC=CC4=[N+]3CC.[I-]
InChI KeyGMYRVMSXMHEDTL-UHFFFAOYSA-M
Synonym(E)-1-Ethyl-2-((1-ethylquinolin-2(1H)-ylide ne)methyl)quinolin-1-ium iodide
CAS No.63902-24-9
PubChem CID5484462

Safety Data

Pictogram
Toxic
Signal Word
Gefahr
Hazard Statement(s)
H330-H312-H315-H319-H335
Precautionary Statement(s)
P260-P264-P280-P302+P352+P312-P304+P340+P310-P305+P351+P338

Synthetic Route by SureRoute

1. ACCOKV517 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Plus
  3. reactant_2 route compound structure diagram
    --
  4. Then
  5. ACCOKV517 route product structure diagram
    ACCOKV51763902-24-9 In Stock
Inquiry

2. ACCOKV517 Molecular Building Block Synthetic Route

Source: SureRouteAuthor: aifchem

  1. reactant_1 route compound structure diagram
    --
  2. Plus
  3. reactant_2 route compound structure diagram
    --
  4. Then
  5. ACCOKV517 route product structure diagram
    ACCOKV51763902-24-9 In Stock
Inquiry

Comments (0)